If pq st pqr 110 and rst 130 find qrs
Web11 apr. 2024 · EXERCISE 15A Find the volume, the lateral surface area and the total the cuboid whose dimensions are: (i) length = 12 cm, breadth = 8 cm and height = 4.5 cm (ii) length = 26 m, breadth = 14 m and height = 6.5 m iii) length = 15 m, breadth = 6 m and height = 5 dm iv) length = 24 m, breadth = 25 cm and height = 6 m A matchbox … Web18 apr. 2024 · In the given figure if PQ ST, ∠PQR = 110° and ∠RST = 130°, Find ∠QRS Solution: From point R draw a line RM parallel ST. ∠RST + ∠SRM = 180° 1 (Consecutive interior angle) or, 130° + ∠SRM = 180° ∴∠SRM = 50° … (i) Now, ∠QRM = ∠PQR or, ∠QRM = 110° or, ∠QRS + ∠SRM = 110° or, ∠QRS + 50° = 110° (from (i)) ∴∠QRS = 60°
If pq st pqr 110 and rst 130 find qrs
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WebIn the figure, if PQ ST, ∠PQR = 1100 and ∠ RST = 1300, find ∠QRS. Answer: Extend PQ to Y and draw LM ST through R. ∠TSX = ∠QXS [Alternate angles] => ∠QXS = 1300 ∠QXS ... => 1100 + ∠PQR = 1800 => ∠PQR = 1800 – 1100 = 700 Also, ∠SPR + ∠QPR = 1800 WebExercise 6.1 (Page 96) 1. In the following figure, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE. Ans. Since AB is a straight line, Thus, ∠BOE = 30° and reflex ∠COE = 250. 2. In the …
WebConstruction: A line XY parallel to PQ and ST is drawn. ∠PQR+∠QRX=180 o (Angles on the same side of transversal.) 110 o+∠QRX=180 o. ∠QRX=180 o−110 o. ∠QRX=70 o. Also, … WebIn the given figure, if PQ ST, ∠ PQR = 110° and ∠ RST = 130°, find ∠ QRS. [Hint: Draw a line parallel to ST through point R.] Solution: Given, PQ ST, ∠ PQR = 110° and ∠ RST = 130° Draw a line AB parallel to ST through R. Now, ST AB and SR is a transversal. So, ∠ RST + ∠ SRB = 180°[since, sum of the interior angles on ...
WebIn the given figure, if PQ ST, ∠PQR = 110º and ∠RST = 130º, find ∠QRS. [Hint: Draw a line parallel to ST through point R.] Solution Let us draw a line XY parallel to ST and … Web17 aug. 2024 · Question 4. In figure, if PQ ST, ∠ PQR = 110° and ∠ RST = 130°, find ∠QRS. Solution: Drawing a tine parallel to ST through R. Question 5.
Web4. In Fig. 6.31, if PQ ST, PQR = 110° and RST = 130°, find QRS. [Hint : Draw a line parallel to ST through point R.] Solution: First, construct a line XY parallel to PQ. We know that the angles on the same side of transversal is equal to 180°. So, PQR+ QRX = 180° Or, QRX = 180°-110° ∴ QRX = 70°
WebClick here👆to get an answer to your question ️ In Fig. \( 6.31 , \) if PQ \( \left\ \) ST, \( \angle P Q R = 110 ^ { \circ } \) and \right \( \angle R S T = 130 ... parks and trees actWebThus, ∠AGE = 126°, ∠GEF = 36° and ∠FGE = 54° 4. In the following figure, if PQ ST, ∠PQR = 110° and ∠RST = 130°, find ∠QRS. Hint: Draw a line parallel to ST through point R. Ans. ∴ PQ ST [Given] and EF ST [Construction] ∴ PQ EF tim matheson\u0027s ageWebIn figure, if PQ ST, ∠PQR = 110° and ∠RST = 130°, find ∠QRS. [Hint. Draw a line parallel to ST through point R.] 363 Views Switch Flag Bookmark In figure, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE. 1248 Views Answer In figure, if x + y = w + z, then prove that AOB is a line. 512 Views Answer tim matheson megan murphy mathesonWeb11 apr. 2024 · EXERCISE 15A Find the volume, the lateral surface area and the total the cuboid whose dimensions are: (i) length = 12 cm, breadth = 8 cm and height = 4.5 cm (ii) … tim matheson movies listWebIn Fig. 6.33, PQ and RS are two mirrors placed parallel to each other. An incident ray AB strikes the mirror PQ at B, the reflected ray moves along the path BC and strikes the mirror RS at C and again reflects back along CD. parks and trails districtWebIn fig. 6.31, if PQ is parallel to ST `/_PQR` = 110 and `/_RST = 130` find `/_QRS` 10,882 views Oct 12, 2024 207 Dislike Share Save Doubtnut 2.38M subscribers To ask Unlimited Maths... tim matheson role in virgin riverWeb28 mrt. 2024 · Let AB PQ, drawn through point M Since PQ RS, AB RS Since AB PQ and MX is the transversal XMB + QXM = 180 XMB + 135 = 180 XMB = 180 135 XMB = 45 Similarly, Since AB RS and MY is the transversal BMY = RYM BMY = 40 Now, XMY = XMB + MBY XMY = 45 + 40 XMY = 85 Next: Example 5 → Ask a doubt Chapter 6 Class … tim matheson tv roles